Jim Wakefield managed to bring the Indus foot to my attention – it’s about 13.2 inches or 13.2 / 12 = 1.1 feet. I’d rather shy away from the subject because it could have been tough determining just how many feet that was supposed to be (1.111111111 for starters?), but I finally noticed that 13.2 x 1.5 = 19.8, and I’d long been curious about a unit of measurement called the Pole that was mentioned in one of Henry Lincoln’s books, of 198 inches.
I’d already figured out that the Pole might be suitable for geodetic modelling at the ratio of feet:mile x 10^n, because 24901.19742 / (4 Pi) = 198.1574329 x 10, so 198.1574329 / 15 = 13.21049553 inches / 12 = 1.100874627 became my nomination for the Indus foot and is still my favorite of several.
The other nomination is, hopefully not surprisingly
(1.100874627 / 1.000723277 = 1.100078965)
So, having recently done some revisiting the concept of describing the origins of, or relationship between, metrological units via the geometry of squares and rectangles such as 2 Remens being the diagonal to 1 Royal Cubit, or the Palestine Cubit being the diagonal to a rectangle of 1 Remen by 1 Royal Cubit and etc, it finally occurred to me that maybe an Indus Foot should have a place in such proceedings.
To use my favorite putative value of 1.100874627 ft for the Indus foot, along with my other standard values
A rectangle of 1 Indus Foot by 1 Remen has a diagonal of
sqrt (( 1.100874627^2) + (1.216733603^2)) = 1.640842956 = 3.281685911 (1 meter in feet = ~3.28084)
A rectangle of 1 Indus Foot by 1 Royal Cubit has a diagonal of
sqrt ((1.100874627^2) + (1.718873385^2)) = 2.041188541 ft
Berriman’s value for a “Karnak Cubit” (so to speak) is 20.412 inches
A rectangle with width of 1 Indus Foot with a diagonal of 1 Remen has a length of
sqrt ((1.216733603^2) – (1.100874627^2)) = 1.320076047 = .1100063370 x 12
A rectangle with width of 1 Indus foot with a diagonal of 1 “Ellifino” of 1.921388691 feet has a length of
sqrt ((1.921388691^2) – (1.100874627^2)) = 1.57471108
A value of ~1.57471108 has been appearing in the Stonehenge data in this series. 1.57471108 is roughly near to the square root of the polar circumference in miles (sqrt 24860 = 1.576705426 x 10^n).
The “Ellifino” (a play on the “ell” or “elle”, an old name for cubit) is called that because ‘ell if I know what it is – it appears to be a lost metrological unit that is about sqrt 5 to the half Royal Cubit, and about sqrt 2 to the Megalithic Yard (hence 1.921388691 is close to the square root of 1/2 of a squared Megalithic Yard such as Munck’s), but even after tentatively placing 1.067438159 ft as a possibly much earlier appearance of the pied du roi, I still cannot seem to match 1.921388691 ft to a known metrological unit.
Given its relationship to other units as shown, it should likely have been a legitimate metrological unit in its own right, but I still cannot place it.
Also, I might note that 13.2 x sqrt 3 = 22.86307066. It might not be a match, but recently I’ve had some cause to be looking at figure near to about 22.88-something.
Perhaps we will learn more about these things in the near fugure.
–Luke Piwalker
Luke Piwalker 