MORE AUBREY CENTER DISPLACEMENT EXPERIMENTS
In Part 9 of this series, we looked the effect of the Aubrey Center displacement on the proportioning of the mean Trilithon “horseshoe” ellipse along its major axis (major diameter), and the we took a look at is effect on the proportioning of the outer bluestone circle.
For the mean ellipse, we observed that (28.5 / 2) – 1.5 = 12.75 MY = ~34.68 ft
And that this is suspiciously close to the “textbook” (Wikipedia) figure of 346.62 days for the Eclipse Year.
Now let’s look at the inner bluestone circle, with a diameter of ~17 MY, according to Professor Thom.
(17 / 2) + 1.5 = 10 MY x 2.72 = ~27.20 ft
(17 / 2) – 1.5 = 7 MY x 2.72 = ~19.04 ft
There is a remarkable number I first encountered at Tikal. I ended up writing a post specifically devoted to it.
http://grahamhancock.com/phorum/read.php?1,1198957,1203919#msg-1203919
Being this magical mystery number is 1.424280287, would it surprise the reader to know that 27.20174976 / 19.09859317 (60/Pi) = 1.424280287?
I think that one might actually be more less solved already? The main components, at least.
Next let’s try something particularly impetuous. Surely it’s not a surprise that the mean of the two Trilithon ellipses that contain the Trilithon “horseshoe” might turn out to have an intentional-looking mean value, but how about the mean of the inner Trilithon ellipse and the bluestone ellipse?
Surely that must be stretching things too far, right?
Well, this would be the mean of two ellipses described by Professor Thom as 27 x 17 MY and 22 x 14 MY, so
(27 + 22) / 2 = 24.5 MY x 2.72 = ~66.64 ft
(17 + 14) / 2 = 15.5 MY x 2.72 = ~42.16 ft
24.5 / 15.5 = 1.580645161
I don’t think I want to try to solve that right now, but I would like to note that 42.16 ft in Remens is about 42.16 / 1.2167 = 346.5110545, since we’ve been talking about how Stonehenge is starting to throw figures at use that are reminiscent of the “346.62” day Eclipse Year.
There’s another one – so yes, this almost looks like something we were intended to do in our interpretation.
What I’d like to do here is just see how the Aubrey Center offset affects the proportions here
(24.5 / 2) + 1.5 = 13.75 MY x 2.72 = ~37.4 ft
(24.5 / 2) – 1.5 = 10.75 MY x 2.72 = ~29.24 ft
Yet these figures look less mysterious. The first figure looks like “Alternate Pi” / Pi, or 1.177245771 / Pi = the marvelous number 3.747289674.
Speaking of the possibility of Stonehenge being a profoundly well designed calendrical calculator mathematically speaking (in addition to who knows what all else), the same may be said of the Aztec (and Mayan) calendar stones (“circular altars”), and 1.177245771 / Pi = 3.747289674 seems to feature prominently in the design of what may be the best known of them all, the Aztec Sun Stone
http://grahamhancock.com/phorum/read.php?1,1198957,1203987#msg-1203987
Interpreted as measuring
Radius 1.873644837 ft – Diameter 3.747289674 ft – Circumference 11.77245771 ft – Thickness 1 = 32.27486122 = (1 / sqrt 960) = 1 / 30.98386677 ft – Thickness 2 = 3.225153443 = (1 / (Pi^3)) = (1 / 31.00627668) ft
~29.24 ft might want to tempt us with exotic possibilities like “The Mayan Annoyance” 29.26442327, but the safer bet might be 24 Remens = 29.20160646, a potent geodetic modelling figure.
37.47289674 / 29.20160646 = 1 / 779.2727272, 779.2727272 being a fairly well established figure now for the diameter of the outer bluestone ring, and still striving for acceptance as one valid representation of the 779.96 day Mars Synodic Period.
I have to say, I’m rather amazed at the way Stonehenge seems to balance redundancy (backup) with the incorporation of new numbers. I’m very impressed, and I’m not very easily so impressed.
What then are the hopefully now “fine-tuned” figure 37.47289674 and 29.20160646 in Megalithic Yards?
29.20160646 / 2.720160646 = 10.73519414.
Always happy to see that figure. If it’s going to turn up at Stonehenge, someone should put (Pi / 3) near to it so we can set off the same fireworks display as at Tikal when 10.73519414 and (Pi / 3) are combined.
Oh, wait, someone did put (Pi / 3) near to it at Stonehenge, as if they knew precisely what they were doing.
37.47289674 / 2.720160646 = 1.377591407
37.47289674 / 2.719256444 = 1.378056742
And what are those?
Well, I’ve already mentioned how Stonehenge seems to be flinging some unexpected calendrical figures at us – and not just a ~346.62 day Eclipse Year, but also some numbers that look suspiciously like the lunar Anomalistic Month of 27.554549886 days (Wikipedia)
So, quite intriguingly,
1.377591407 x 2 = 27.55182814
1.378056742 x 2 = 27.56113483
We may get this figured out yet if Stonehenge keeps giving us so much help.
–Luke Piwalker
Luke Piwalker 