Being it is near to Dzibilchaltun on the list, I happened to notice the omission of data for the Mayan site Dsecilna. It might have happened because the site is probably rather ruinous and there were more intact ones that called for attention.
I don’t know if I can conjure enough for a decent blog post, but I could try.
George Andrews says of Dsecilna in Architectural survey Puuc archaeological region : 1984 field season. Volume 3,
DSECILNA (DZEKILNA) NUMBER:16 Qd (10): 143 DATE: 1/25/1984
BACKGROUND Stephens (1843) was the first person to report on this site although he did not record any architectural data. Maler (1895) explored the site more thoroughly and described several very large groups of structures and numerous smaller mounds, which he said were spread along both sides of the wagon road between the Hacienda Yaxche and the town of Santa Elena. Pollock (1980) made brief reference to the site and to Maler’s notes but did not visit the site himself. I visited the site in January of 1984, accompanied by my wife and and Carlos Perez and Lourdes Toscano of the CRY, INAH. We examined a badly fallen pair of structures standing on a huge platform near the southern edge of the site (South Group). Maler noted the same group, which he indicated was about one kilometer south of the “northern group of buildings”, and said that the buildings were “more recent”. Dunning (1987) paid a brief visit to the site but found it very overgrown, with the result that he was unable to make a sketch map or to record any architectural data.
I’ll start by pointing out that for Structure 1, Room 9, the width in feet resembles the Nodal Cycle and the door width resembles the Lunar Month
Width 2.12 m at doorway = 6.955380577 ft
Door .90 m wide = 2.9527559055 ft
Sadly, the length of the same room is uncertain as Andrews gives a figure of ~5.17-5.47 m = ~16.962-17.946 but it isn’t clear to me if these are the lengths of both long walls or an uncertain average.
For Structure 2,
Room 1
Length 10.75 m 35.269028871
Width 2.36 m 7.7427821522
Room 2
Length 8.73 m 28.6417322834
Width 2.50 m 8.20209973753
Room 3
Length 2.22 m 7.28346456692
Width 2.50 m 8.20209973753
Room 4
Length 6.86 m 22.5065616797
Width 2.82 m 9.25196850393
Comments:
Room 1: The width certainly looks like sqrt 60 ft, while the length I am much less certain about. I think similar figures appear in others’ work (I believe rodz works with 352 and 352.80) but I not am certain I understand what they are supposed to represent, nor the need for them. Are they perhaps supposed to be approximations of the Lunar Year?
The ratio between length and width may be a simple fraction of some form of the Solar Year, and the product of length x width in “modern” feet may represent the Tropical Year.
Room 2: Offhand it looks like the half Radian and the inverse form of the Remen, which is probably reminiscent of Stonehenge. The combination is able to yield the triple Venus Orbital Period and the Cuicuilco Number (formed from Royal Cubit and Hashimi Cubit), and possibly more astronomical data.
Room 4: The Venus Orbital Period ~225 d seems rather blatant here. The width value probably won’t get away with being the reciprocal of the Saturn Orbital Period and is probably more like the reciprocal of 1.067438159 / (Pi^2)).
The ratio between length and width looks like about 2 Remens in feet, and the product of the two in feet (i.e., floor area) looks like either the reciprocal of 480, or of Munck’s height for the Great Pyramid = 480 x 1.000723277.
The figure 1.676727943, which both the Maya and the ancient Egyptians seem to have favored, can be obtained by combining the latter with the apparent Half Radian from “next door”.
The product of length x width of Room 3 itself (1 / 1.6737454747) may likely be 1/1.676727943 or 1/1.6713128806 (see Sacred Cubit, now tentatively identified with Thom’s Mid Clyth Quantum = sqrt 60 ft?).
The latter with Pi produces the number of minutes in a year, while the former with Pi produces Half Venus Cycle A and half of 1.067438159.
This would require (1 / 1.676727943) / (1 / Remen), and with the standard Remen of 1.216733603, that gives
(1 / 1.676727943) / (1 / 1.216733603) = 7.256595252 / 10^n. I’m not certain if that’s intentional, but it turns out this is the square root of the reciprocal of Half Venus Cycle C, which is something I’m fairly sure I didn’t know.
7.256595252 neatly combines with Venus Orbital Period A to yield the reciprocal of sqrt 960, and 1.1772457716^3, but stops short of being able to express the reciprocal of the Lintel Megalithic Yard.
It’s interesting because 1.177245771^3 has been too rare of a constant so far. No doubt ancient people would know what it was.
Sqrt 60 elicits 1.067438159 from 7.256595252: sqrt 60 / 7.256595252 = 1.067438159
“Incidentally”, (1 / 1.676727943) x (1.067438159^2) = 6795.522363 / 10^n
A series formed by combining (1 / Remen) with sqrt 60 includes 1 / 73.00401618 = 365.0200808 / 5, and a possible figure for the Lunar Leap Month (SMMY x 2^n). The series seems more impressive in reciprocal form. (It may already be self evident to the reader that the measures of this site seem to lean toward expression of important numbers in reciprocal form).
Perhaps it merits emphasis that because for Room 4, the ratio between length and width is about 2 Remens in feet, that the Remen seems to have been represented as both measure and ratio. This kind of gesture became something that seemed rather typical for Egypt, and lately it seems to have been common in ancient America as well.
Some other items from Structure 1 that might be of interest
S1 R5 Length 8.31 m = 27.263779527 ft = ~Tropical / Sidereal Month
S1 R15 Width 2.23 m = 7.3162729658 ft = ~365 / 5
S1 R15 Doors 1.05 m wide = 3.4448818897 ft = ~3.4662?
Possible references to the Tropical / Sidereal Year AND ~1/5 of the Solar Year (~73) already seem to have appeared in the proceedings for Structure 2. Doors “One Eclipse Year” (in feet) wide would be fitting after how many Mayan doors I’ve seen lately that seem to measure “One Solar Year” (in feet) wide. Also, for Structure 1, Room 17, the door in the East wall is .83 m = 2.723097112 ft wide. 2.73 feet = ~.8321 meters.
However, I’m not as certain as I wish I were which form of the Solar Year is being divided here by 5 to produce ~73.
The classic is of course 365.0200808 / 5 = 73.00401616 but a sqrt 60 series exists which includes 360 / 29.52390320, 7.31610582 (365.805291 / 5), 340.021872, and 9.48173143.
The length 2.89 m = 9.481627297 appears as the width of Structure 1, Room 7.
A measure of 4.32 m = 14.1732283464 ft seems to recur in structure 1. It may represent 2 / (Megalithic Foot in Inches) =
2 / (1.177245771 x 12) = 1.415733832 = 1 / (Venus Orbital Period x Pi) = 4.315 m.
In Room 17, a length of 4.32 m is paired with widths of 3.07 m = 10.0721784776 ft at the end wall and 3.20 m = 10.4986876640 ft at center, which could be 10.47197551 = 10 x (Pi / 3), a very desirable addition, granting a possible error of ~1 cm on Andrew’s part due to the condition of the site. 10.0721784776 might represent 10.06036766 if it proves to be sensible component. The resultant Pi / 3 series would probably be worthy enough and is at least mildly interesting – it includes as many as three astronomical figures on the upper end and the number of hours in a year of 365.0200808 days on the lower end. The series is also able to find 364.2365561 / 2, 364.2365561 being a promising experimental version of “364”.
The ratio between 3.20 and 3.07 = 3.20 / 3.07 = 1.0423445277 = ~1.040913798, which actually is the ratio of (Pi / 3) and 10.06036766. The product of the two would be 10.47197551 x 10.06036766 = 105.3519238 = (2 / 18983.99126) x 10^n
I’ve written about it before recently including https://pijedi.home.blog/2020/09/05/maya … ereabouts/
https://pijedi.home.blog/2020/08/29/a-st … h-for-364/
1.415733832 is part of an extremely powerful Pi / 3 series. It’s in fact none other than one of the most impressive exponential series from Tikal
(1.415733832 x 10^n) / ((Pi / 3)^1) = 1 / Squared Munck Megalithic Yard
(1.415733832 x 10^n) / ((Pi / 3)^2) = 1.290994449 = 1 / sqrt 60
(1.415733832 x 10^n) / ((Pi / 3)^3) = 1.232808888 = 2 / 1.622311470
(1.415733832 x 10^n) / ((Pi / 3)^4) = 1.177245771 = “Alternate Pi” and/or Megalithic Foot
(1.415733832 x 10^n) / ((Pi / 3)^5) = 224.8373808 / 2 = Venus Orbital Period A / 2
etc, etc
Notice the ranking of these numbers in the graph from yesterday’s posts. Coupling (Pi / 3) to 1/2 of the Venus Orbital produces a stunning string of the most important constants.
Lately I’ve been posting my blog a bit about “justification” – which is when I find that one of my crazy numbers closely resembles a crazy number that ancients would have encountered in the line of duty as astronomers and calendar keepers, and there are number of these instances now noted – for example, the classic Saros 6585.3211 / 19 = 346.5958744, which probably resembles my main Eclipse Year of 346.5939351 more than it does anything else.
Since I’m going on about the number 1.676727943, I will repeat that this goes into the projected height of the Great Pyramid’s missing apex section (which may have been considerably larger than the final pyramidion itself):
167.6727943 / 6 = 27.94546572 ft = total apex section height.
I should perhaps point out that the raw value of Calendar Round 18980 / Nodal Cycle 6793 = 2.794052701, not to mention the connections that 27.94546572 has to the Venus Orbital Period and other important calendar numbers.
What’s the most important number expressed by the Great Pyramid? Of course. It’s the perimeter/height ratio of 2 Pi.
2 Pi / 27.94546572 = 224.83738080 / 100
Where do I get these crazy ideas? 😉
–Luke Piwalker
Luke Piwalker 